Practicing Success
Fig. shows three similar lamps L1, L2 and L3 connected across a power supply. If the lamp L3 fuse, how will the light emitted by L1 and L2 change ? |
no change brilliance of L1 decreases and that of L2 increases brilliance of both L1 and L2 increases brilliance of both L1 and L2 decreases |
brilliance of L1 decreases and that of L2 increases |
Let R be the resistance of each lamp. If E be the applied e.m.f., then the current in the circuit, I1, is given by I1 = $\frac{E}{R+(R / 2)}=\frac{2 E}{3 R}$ Current flowing through L2 or L3 = $\frac{1}{2}\left[\frac{2 E}{3 R}\right]=\frac{E}{3 R}$ When L3 is fused, the whole current flows through L1 and L2. Thus I2 = $\frac{E}{R+R}=\frac{E}{2 R}$ So, current through L1 decreases and through L2 increases. Hence option (b) is correct. |