Solve the following equation and find the value of θ. $3cotθ + tanθ - 2\sqrt{3}=0, 0< θ < 90°$

30° 45° 60° 15°

60°

3 cotθ + tanθ - 2√3 = 0 3 × \(\frac{1}{tanθ}\) + tanθ - 2√3 = 0 tan²θ  - 2√3 tanθ + 3 = 0 On solving, tanθ = √3 { we know, tan 60º = √3 } So, θ = 60º