PQR is an isosceles triangle such that PQ = QR = 10 cm and ΔPQR = 90°. What is the length of the perpendicular drawn from Q on PR?
Answer & explanation
Correct answer: option 4
We know that,
Area of triangle = (1/2) × Base × Height
(Hypotenuse)2 = (Base)2 + (Perpendicular)2
We have,
PQ = QR = 10 cm
∠PQR = 90°
PR2 = 102 + 102
= PR2 = 100 + 100
= PR2 = 200
= PR = 10√2
We know that,
= (1/2) × 10 × 10 = (1/2) × QM × 10√2
QM = 5√2 cm.