The equivalent capacitance between the points A and B in the network given below is
Answer & explanation
Correct answer: option 1
The given circuit is a balanced Wheatstone bridge of capacitors, hence P.D across bridge capacitor of5 μF is zero.
Thus, the circuit can be modified as
\( C_{n e t}=\left(\frac{1}{30}+\frac{1}{60}\right)^{-1}=\left(\frac{1}{20}\right)^{-1}=20 \mu \mathrm{F} \)