Practicing Success
Two nuclei have mass number in the ratio 1:27, then the ratio of their radii and densities should be respectively |
1 : 1 and 1 : 3 1 : 9 and 1 : 1 1 : 3 and 1 : 1 1 : 1 and 1 : 9 |
1 : 3 and 1 : 1 |
We know, Radius of Nucleus \( R \propto A^{1 / 3} \) Where A is mass number ∴ \(\frac{R_1}{R_2} = \left(\frac{1}{27}\right)^{\frac{1}{3}} = \frac{1}{3}=1: 3 \) While nuclear density is same for all nuclei $ \rho = \frac{M}{V} = \frac{m_p A}{\frac{4\pi }{3} r^3} = \frac{3m_p A}{4\pi k A} = \frac{3m_p }{4\pi k}$ $ \rho$ is independent of A. ∴ \( \frac{\rho_1}{\rho_2}=1: 1 \) |