CUET Preparation Today
In the circuit shown in figure, if the diode forward voltage drop is 0.3 V. the voltage difference between A and B is.
|
1.3 V 2.3 V 0 0.7 V |
2.3 V |
The correct answer is Option (2) → 2.3 V From Kirchhoff’s voltage law
$V_A-0.2 \times 10^{-3} \times 5 \times 10^3-0.3$ $-0.2 \times 10^{-3} \times 5 \times 10^3=V_B$ $V_A-V_B=1+0.3+1=2.3 ~V$ |
