If sin A =1/2, then the value of (tan A + cos A) is:

We are given that :-

sinA = \(\frac{1}{2}\)

{ we know, sinA = \(\frac{P}{H}\) }

By using pythagoras theorem,

P² + B² = H²

1² + B² = 2²

B² = 4 - 1

B = \(\sqrt {3 }\)

Now,

tanA + cosA

= \(\frac{P}{B}\) + \(\frac{B}{H}\)

= \(\frac{1}{ √3 }\) + \(\frac{√3}{2}\)

= \(\frac{5}{ 2√3 }\)