CUET Preparation Today
The difference between mean and variance of a binomial distribution is 4 and the difference of their squares is 32. Then distribution is given by : |
$\left(\frac{1}{3}+\frac{2}{3}\right)^{36}$ $\left(\frac{1}{8}+\frac{7}{8}\right)^{36}$ $\left(\frac{1}{8}+\frac{7}{8}\right)^{8}$ $\left(\frac{1}{3}+\frac{2}{3}\right)^{9}$ |
$\left(\frac{1}{3}+\frac{2}{3}\right)^{9}$ |
