Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B2

Chapter

Probability Distributions

Question:

The difference between mean and variance of a binomial distribution is 4 and the difference of their squares is 32. Then distribution is given by :

Options:

$\left(\frac{1}{3}+\frac{2}{3}\right)^{36}$

$\left(\frac{1}{8}+\frac{7}{8}\right)^{36}$

$\left(\frac{1}{8}+\frac{7}{8}\right)^{8}$

$\left(\frac{1}{3}+\frac{2}{3}\right)^{9}$

Correct Answer:

$\left(\frac{1}{3}+\frac{2}{3}\right)^{9}$