If A = \(\begin{bmatrix}3 & 3\\6 & 8 \end{bmatrix}\), then what can be said about 24\( { A }^{ -1 } \)?

24\( { A }^{ -1 } \) = 4 (adj A)

\( { A }^{ -1 } \) =\(\frac{adj A}{|A|}\)

But |A| = 6

So, \( { A }^{ -1 } \) =\(\frac{adj A}{6}\)

     24 \( { A }^{ -1 } \) = 24 \(\frac{adj A}{6}\)

                                     = 4 (adj A)