In a circle with center O, an arc ABC subtends an angle of 142° at the center of the circle. Chord AB is produced to point P, then ∠CBP is equal to?
Answer & explanation
Correct answer: option 2
∠ADC = \(\frac{142}{2}\) = 71°
∠ABC = 180° - 71° = 109° (cyclic quad.)
∠CBP = 180° - 109° = 71°