In a circle with center O, an arc ABC subtends an angle of 142° at the center of the circle. Chord AB is produced to point P, then ∠CBP is equal to? |
99° 71° 119° 121° |
71° |
∠ADC = \(\frac{142}{2}\) = 71° ∠ABC = 180° - 71° = 109° (cyclic quad.) ∠CBP = 180° - 109° = 71° |