By Interchanging the given two numbers which of the following equation will be correct? 1 and 6 I. 7 - 5 + 1 x 3 ÷ 6 = 20 II. 1 x 7 + 6 - 4 ÷ 2 = 40 |
Only I Neither I nor II Both I and II Only II |
Only I |
In the first equation, 7 - 5 + 1 x 3 ÷ 6 = 20 interchanging 1 and 6, The equation becomes 7 - 5 + 6 x 3 ÷ 1 = 20 The equation is correct, i.e. LHS = RHS BY interchanging in the second equation : 1 x 7 + 6 - 4 ÷ 2 = 40 The equation becomes 6 x 7 + 1 - 4 ÷ 2 = 40 Here, LHS = 41 and RHS = 40 Thus, interchanging does not make the equation correct. |