A 200 kg wagon climbs up a hill of slope 30-degrees in 1 minute at a speed of 36 km/h. How much power is delivered by the engine if the frictional force is 25% of the weight of the car? (Assume g = 10m/s²)

25 kW

Weight of car = m x g

    = 200 x 10 = 2000 N

Frictional force = \(\frac{25}{100}\) x (2,000)

    = 500 N

Total force (F) = (2000 + 500) N

    = 2500 N

Velocity (v) = 36 km/h

    = 36 x \(\frac{100}{3600}\)

    = 10 m/s

P = F x v

   = (2500 x 10) W = 25 kW.