A 200 kg wagon climbs up a hill of slope 30-degrees in 1 minute at a speed of 36 km/h. How much power is delivered by the engine if the frictional force is 25% of the weight of the car? (Assume g = 10m/s2)
Answer & explanation
Correct answer: option 1
Weight of car = m x g
= 200 x 10 = 2000 N
Frictional force = \(\frac{25}{100}\) x (2,000)
= 500 N
Total force (F) = (2000 + 500) N
= 2500 N
Velocity (v) = 36 km/h
= 36 x \(\frac{100}{3600}\)
= 10 m/s
P = F x v
= (2500 x 10) W = 25 kW.