Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section A

Chapter

Applications of Derivatives

Question:

The function $f : [0, 1] → R$ given by $f(x)=\alpha x^3$ has

Options:

maximum value $\frac{1}{8}$ when $\alpha=1$

minimum value $-\frac{1}{8}$ when $\alpha=-1$

minimum value -1 when $\alpha=-1$

maximum value 1 when $\alpha=-1$

Correct Answer:

minimum value -1 when $\alpha=-1$

Explanation:

The correct answer is Option (3) - minimum value -1 when $\alpha=-1$