Find the HCF of \(\frac{3}{7}\) , \(\frac{2}{5}\) , \(\frac{5}{11}\) ?

\(\frac{13}{385}\) \(\frac{11}{385}\) \(\frac{1}{385}\) \(\frac{3}{385}\)

\(\frac{1}{385}\)

The HCF of \(\frac{3}{7}\), \(\frac{2}{5}\) and \(\frac{5}{11}\) H.C.F. of fractions = \(\frac{HCF\;of\;numerator}{LCM\;of\;denominator}\)                           = \(\frac{HCF of (3,\;2,\;5)}{LCM of (7,\;5,\;11)}\)                           = \(\frac{1}{385}\)