Find the HCF of \(\frac{3}{7}\) , \(\frac{2}{5}\) , \(\frac{5}{11}\) ?

\(\frac{1}{385}\)

The HCF of \(\frac{3}{7}\), \(\frac{2}{5}\) and \(\frac{5}{11}\)

H.C.F. of fractions = \(\frac{HCF\;of\;numerator}{LCM\;of\;denominator}\)

                          = \(\frac{HCF of (3,\;2,\;5)}{LCM of (7,\;5,\;11)}\)

                          = \(\frac{1}{385}\)