The products \(X\) and \(Y\) for the below reaction are:

The correct answer is option 3.

The reaction is as follows:

Nitro group is a deactivating and m-directing group hence it directs the incoming \(Br^-\) ion to the m-position, thus leading to the formation of m-bromonitrobenzene. By reduction with \(Sn/HCl\), the nitro group reduces to \(NH_2\), i.e.,  the final product is m-bromoaniline.