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The slope of the normal to the curve $y = 2x^2$ at $x = 1$ is: |
4 -4 1/2 -1/4 |
-1/4 |
The correct answer is Option (4) → -1/4 Given curve $y=2x^2$ Slope of tangent $\frac{dy}{dx}=4x$ At $x=1$ $m_{\text{tangent}}=4$ Slope of normal $m_{\text{normal}}=-\frac{1}{m_{\text{tangent}}}$ $=-\frac{1}{4}$ The slope of the normal at $x=1$ is $-\frac{1}{4}$. |
