If $3 \sin θ-4 \cos θ=0$, then value of $\tan θ.cosec θ$ is:

$\frac{4}{3}$ $\frac{16}{15}$ $\frac{5}{3}$ $\frac{12}{5}$

$\frac{5}{3}$

The correct answer is Option (3) → $\frac{5}{3}$