If confidence interval for population parameter µ is (180, 200), then margin of error is: |
10 190 20 110 |
10 |
The correct answer is Option (1) → 10 $\text{Margin of error} = \frac{\text{Upper limit} - \text{Lower limit}}{2}$ $= \frac{200 - 180}{2} = \frac{20}{2} = 10$ $\text{Margin of error} = 10$ |