Practicing Success
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The internal energy change in a system that has absorbed 2 Kcals of heat and done 500 J of work is: |
6400 J 5400 J 7900 J 8900 J |
7900 J |
Q = \(\Delta\) U + W \(\Delta\) U = Q - W = 2 x 4.2 x 1000 - 500 = 7900 J |
