If ΔABC∼ΔFDE such that AB = 9 cm, AC = 11 cm, DF = 16 cm and DE = 12 cm, then the length of BC is:
Answer & explanation
Correct answer: option 4
AB = 9 cm,
AC = 11 cm,
DF = 16 cm and DE = 12 cm
So, \(\frac{ AB }{ DF }\) = \(\frac{ AC }{ FE }\) = \(\frac{ BC }{ DE }\)
So,
\(\frac{ AB }{ DF }\) = \(\frac{ BC }{ DC }\)
= \(\frac{ 9 }{ 16 }\) = \(\frac{ BC }{ 12 }\)
= BC = 27/4 = $6\frac{3}{4}$ cm