CUET Preparation Today
If Max $Z=x+2y $ subject to $x+y ≥ 4, 3x+2y ≤ 12, x ≤ 2, x, y ≥ 0. $ Then for optional solution of above LPP _____________ . |
$Z=12$ $Z=18$ $Z=16$ $Z=24$ |
$Z=12$ |
The correct answer is Option (1) → $Z=12$
The objective function is, $Z=x+2y$ $Z_{max}(0,6)=0+2×6$ $=12$ is the max. value |
