If Max $Z=x+2y $ subject to $x+y ≥ 4, 3x+2y ≤ 12, x ≤ 2, x, y ≥ 0. $
Then for optional solution of above LPP _____________ .
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → $Z=12$
The objective function is,
$Z=x+2y$
$Z_{max}(0,6)=0+2×6$
$=12$ is the max. value