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If 5sin2A + 3cos2A = 4, 0° < A < 90° find the value of sin2θ + sec2θ + cotθ |
\(\frac{7}{2}\) 1 4 \(\frac{3}{4}\) |
\(\frac{7}{2}\) |
5sin2A + 3cos2A = 4 = 2sin2A + 3sin2A + 3cos2A = 4 = 2sin2A + 1×3 = 4 = 2sin2A = 1 sinA = \(\frac{1}{\sqrt {2}}\) = 45° ⇒ (\(\frac{1}{\sqrt {2}}\))2+(\(\sqrt {2}\))2+1 = \(\frac{1}{2}\)+2+1 = \(\frac{7}{2}\) |
