Let A and B be square matrices of order 3, then det $[(A - A^T) + (B - B^T)]$ is equal to

0

The correct answer is Option (1) → 0

Given:

$A$ and $B$ are square matrices of order 3

Expression: $\det[(A - A^T) + (B - B^T)]$

Observation: $(A - A^T)$ and $(B - B^T)$ are skew-symmetric matrices

Property: Determinant of any odd-order skew-symmetric matrix = 0

Sum of skew-symmetric matrices is also skew-symmetric

Since order = 3 (odd), determinant = 0