Target Exam

CUET

Subject

-- Applied Mathematics - Section B2

Chapter

Calculus

Question:

Match List – I with List – II.

LIST I

LIST II

 A. $y=x^3 \log x$

  I. $\frac{d^2 y}{d x^2}=25 e^{5 x}$ 

 B. $y=e^{5 x}$

 II. $\frac{d y}{d x}=x^x(1+\log x)$ 

 C. $y=x^x$

 III. $\frac{d^2 y}{d x^2}=-\frac{1}{2 a t^3}$ 

 D. $y=at^2, y=2 a t$ 

 IV. $\frac{d^2 y}{d x^2}=x(5+6 \log x)$ 

Choose the correct answer from the options given below:

Options:

A - I, B - II, C - III, D - IV

A - IV, B - II, C - I, D - III

A - IV, B - I, C - II, D - III

A - II, B - III, C - IV, D - I

Correct Answer:

A - IV, B - I, C - II, D - III

Explanation:

The correct answer is Option (3) → A - IV, B - I, C - II, D - III

$\text{(A)}\; y=x^3\log x$

$y'=3x^2\log x + x^2$

$y''=6x\log x + 3x + 2x = x(6\log x + 5) \Rightarrow \text{(IV)}$

$\text{(B)}\; y=e^{5x}$

$y''=25e^{5x} \Rightarrow \text{(I)}$

$\text{(C)}\; y=x^x$

$y'=x^x(1+\log x) \Rightarrow \text{(II)}$

$\text{(D)}\; y=at^2,\; x=2at$

$\frac{d^2y}{dx^2}=\frac{1}{2a t^3}(-1) = -\frac{1}{2at^3} \Rightarrow \text{(III)}$

A–IV,\; B–I,\; C–II,\; D–III