If the particle enters a magnetic field at a certain angle, then what will be the pitch of the path be given by?

2πmv Cos θ/qB 2πv Cos θ/qB πmv Cos θ/qB πmv Cos θ/2qB

2πmv Cos θ/qB

Pitch of the Helical Path: The distance travelled in one time period along the axis of the helical path is called the pitch of the path. Therefore, $theta\}\{qB\}\$$ $\$\; Pitch\; =\; vcos\backslash theta\; T\; =\; vcos\backslash theta\; \backslash times\; \backslash frac\{2\backslash pi\; m\}\{qB\}\; =\; \backslash frac\{2\backslash pi\; m\; v\; cos\backslash theta\}\{qB\}\$$