Practicing Success
Practicing Success
CUET Preparation Today
Find the value of a+2b from the equation $\frac{\sqrt{3}-2}{\sqrt{3}+2}$ = $a+b\sqrt{6}$ |
11 9 11 -2 |
9 |
$\frac{\sqrt{3}-\sqrt{2}}{\sqrt{3}+\sqrt{2}}$ = $a+b\sqrt{6}$ By rationalization, 5 + 2\(\sqrt {6}\) = $a+b\sqrt{6}$ On comparing, a = 5 b = 2 Now put the value of a and b in a+2b, = 5 + 2(2) = 9 |
