Find the value of a+2b from the equation
$\frac{\sqrt{3}-2}{\sqrt{3}+2}$ = $a+b\sqrt{6}$
Answer & explanation
Correct answer: option 2
$\frac{\sqrt{3}-\sqrt{2}}{\sqrt{3}+\sqrt{2}}$ = $a+b\sqrt{6}$
By rationalization,
5 + 2\(\sqrt {6}\) = $a+b\sqrt{6}$
On comparing,
a = 5
b = 2
Now put the value of a and b in a+2b,
= 5 + 2(2) = 9