Practicing Success
If $x^2 +\frac{1}{x^2} = 83, x > 0$, then the value of $x^3 - \frac{1}{x^3}$ is : |
756 675 576 746 |
756 |
If $x^2 +\frac{1}{x^2} = 83, x > 0$, then the value of $x^3 - \frac{1}{x^3}$ We know that, If x2 + \(\frac{1}{x^2}\) = n then, x - \(\frac{1}{x}\) = \(\sqrt {n - 2}\) and we also know that, If x - \(\frac{1}{x}\) = n then, $x^3 -\frac{1}{x^3}$ = n3 + 3 × n If $x^2 +\frac{1}{x^2} = 83, x > 0$, then, x - \(\frac{1}{x}\) = \(\sqrt {83 - 2}\) = 9 Then, $x^3 -\frac{1}{x^3}$ = 93 + 3 × 3 $x^3 -\frac{1}{x^3}$ = 729 + 27 = 756 |