Practicing Success
A random variable X has the following distribution :
The value of k is : |
$\frac{1}{10}$ -1 $\frac{-1}{10}$ $\frac{1}{9}$ |
$\frac{1}{10}$ |
The correct answer is Option (1) → $\frac{1}{10}$ $∑P_i(x_i)=1$ $9k+10k^2=1$ $10k^2+9k-1=0$ $10k^2+10k-k-1=0$ $10k(k+1)-1(k+1)=0$ $(10k-1)(k+1)=0$ so $k=\frac{1}{10}$ as $k≠-1$ |