The value of $\frac{(0.321)^3+(0.456)^3-(0.777)^3}{0.9 \times (0.107)(0.76)(0.777)}$ is
Answer & explanation
Correct answer: option 2
We know that if,
a + b + c = 0
Then, a3 + b3 + c3 = 3abc
$\frac{(0.321)^3+(0.456)^3-(0.777)^3}{0.9 \times (0.107)(0.76)(0.777)}$
0.321 + 0.456 – 0.777 = 0
Then 0.3213 + 0.4563 – 0.7773 = – 3 × 0.321 × 0.456 × 0.777
$-3 \times \frac{(0.321)\times(0.456)\times(0.777) }{0.9 \times (0.107)(0.76)(0.777)}$
$\frac{(0.321)^3+(0.456)^3-(0.777)^3}{0.9 \times (0.107)(0.76)(0.777)}$ = -6