The current in a coil falls from 5 A to 0 A in 0.1 s. If an average emf of 100 V is induced, then the self-inductance of the coil would be-
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → 2 H
The average induced emf in a coil is set by its self-inductance and the rate of change of current.
\( \displaystyle |\varepsilon| = L\,\frac{|\Delta I|}{\Delta t} \;\Rightarrow\; L = \frac{|\varepsilon|\,\Delta t}{|\Delta I|} \)
\( \displaystyle L = \frac{100 \times 0.1}{5 - 0} = 2\,\mathrm{H} \)
Note: NTA picked this question from an NCERT (2026-27) exercise and changed the figures. Do not ignore NCERT while practising numericals.
NCERT (2026-27):
Exercises – …
