In the circuit two identical bulbs $B_1$ and $B_2$ are connected on closing switch S: Which of the following statement is correct?

Bulb $B_2$ lights up earlier than B, and finally both bulbs shine equally bright $B_1$ lights up earlier and finally both bulbs shine equally bright $B_2$ lights up earlier and finally $B_1$ shines brighter than $B_2$ $B_1$ and $B_2$ light up together with same brightness

$B_2$ lights up earlier and finally $B_1$ shines brighter than $B_2$

The correct answer is Option (3) → $B_2$ lights up earlier and finally $B_1$ shines brighter than $B_2$