The value of \(\int { e }^{ -8x } dx\)1\[\frac{{ e }^{ -8x }}{8}\]2\[\frac{{ e }^{ -8x }}{-8}\]3\[\frac{{ e }^{ 8x }}{8}\]4\[\frac{{ e }^{ 8x }}{-8}\]Answer & explanation+Correct answer: option 2the integral will be \[\frac{{ e }^{-8x} }{-8}\]
