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| The value of \(\int { e }^{ -8x } dx\) |
\[\frac{{ e }^{ -8x }}{8}\] \[\frac{{ e }^{ -8x }}{-8}\] \[\frac{{ e }^{ 8x }}{8}\] \[\frac{{ e }^{ 8x }}{-8}\] |
| \[\frac{{ e }^{ -8x }}{-8}\] |
| the integral will be \[\frac{{ e }^{-8x} }{-8}\] |
