Practicing Success
Practicing Success
CUET Preparation Today
A proton and $\alpha$-particle have same kinetic energy. The de-Broglie wavelength ratio $\frac{\lambda_{p}}{\lambda_\alpha}$ is equal to: |
$\frac{m_\alpha}{m_{p}}$ $m_\alpha \times m_{p}$ $\sqrt{\frac{m_\alpha}{m_p}}$ $\sqrt{\frac{m_{p}}{m_\alpha}}$ |
$\sqrt{\frac{m_\alpha}{m_p}}$ |
The correct answer is Option (3) → $\sqrt{\frac{m_\alpha}{m_p}}$ |
