Which of the following pairs of linear equations is/are consistent?
A. \(x+y-5=0,\ 3x+2y-10=0\)
B. \(3x-2y-6=0,\ 6x-4y-12=0\)
C. \(x-y-9=0,\ 3x-3y-27=0\)
D. \(x+y-4=0,\ 3x+3y-12=0\)
Choose the correct option from the given below:
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → A, B, C and D all are Consistent
A pair of linear equations is consistent when it has at least one solution. For \(a_1x+b_1y+c_1=0\) and \(a_2x+b_2y+c_2=0\):
\(\frac{a_1}{a_2}\ne\frac{b_1}{b_2}\): the lines cross, one solution (consistent)
\(\frac{a_1}{a_2}=\frac{b_1}{b_2}=\frac{c_1}{c_2}\): the lines coincide, infinitely many solutions (consistent)
\(\frac{a_1}{a_2}=\frac{b_1}{b_2}\ne\frac{c_1}{c_2}\): the lines are parallel, no solution (inconsistent)
A. x + y − 5 = 0, 3x + 2y − 10 = 0 Consistent. \(\frac{1}{3}\ne\frac{1}{2}\), so the lines cross at one point.
B. 3x − 2y − 6 = 0, 6x − 4y − 12 = 0 Consistent. All three ratios are \(\frac{1}{2}\): the second equation is twice the first, the same line.
C. x − y − 9 = 0, 3x − 3y − 27 = 0 Consistent. All three ratios are \(\frac{1}{3}\): the second equation is three times the first.
D. x + y − 4 = 0, 3x + 3y − 12 = 0 Consistent. All three ratios are \(\frac{1}{3}\), so the two equations give the same line.
Tip: Coincident lines count as consistent; only parallel lines that never meet make a pair inconsistent.