A tap can fill a tank in 3 hours, and a leak can empty in 5 hours. If the tap and the leakage which is half closed are opened together, then find the time taken to fill the tank.
Answer & explanation
Correct answer: option 1
Efficiency:
⇒ Tap - (half closed) leakage = 5 - \(\frac{3}{2}\) = \(\frac{7}{2}\)
Now →
⇒ The required time to fill the tank = \(\frac{15}{7}\) × 2 = \(\frac{30}{7}\) = 4\(\frac{2}{7}\)