A compound forms hexagonal closed packed structure. What is the number of tetrahedral voids in 0.8 mol of it?
Answer & explanation
Correct answer: option 3
The correct answer is option 3. \(9.635 × 10^{23}\).
Number of atoms in close packaging = 0.8 mol
\(1 mol\) has \(6.022 × 10^{23}\) particles
So, the number of close-packed particles \(= 0. 8 × 6.022 × 10^{23} = 4.817 × 10^{23}\)
Number of tetrahedral voids = 2 × number of atoms in close packaging
Plug the values we get
Number of tetrahedral voids \(2 × 4.817 × 10^{23} = 9.6352 × 10^{23}\)