What is the smallest five-digit number which is when divided by 7,11 and 21 leaves a remainder 3 in each case? |
10019 10001 10111 10167 |
10167 |
LCM of 7,11 and 21 = 231 smallest 5 digit number = 10000 multiple of 231 near 10000 = 10164 so, the required number will be = multiple of 231 near 10000 + remainder = 10164 +3 = 10167 (Ans.) |