Practicing Success

Target Exam

CUET

Subject

General Test

Chapter

Numerical Ability

Topic

Number System (1)

Question:

What is the smallest five-digit number which is when divided by 7,11 and 21 leaves a remainder 3 in each case?

Options:

10019

10001

10111

10167

Correct Answer:

10167

Explanation:

LCM of 7,11 and 21 = 231

smallest 5 digit number = 10000

multiple of 231 near 10000 = 10164

so, the required number will be = multiple of 231 near 10000 + remainder =  10164 +3 = 10167 (Ans.)