What is the smallest five-digit number which is when divided by 7,11 and 21 leaves a remainder 3 in each case?
Answer & explanation
Correct answer: option 4
LCM of 7,11 and 21 = 231
smallest 5 digit number = 10000
multiple of 231 near 10000 = 10164
so, the required number will be = multiple of 231 near 10000 + remainder = 10164 +3 = 10167 (Ans.)