Find the LCM of the fractions $\frac{2}{5}, \frac{3}{7}$, and $\frac{4}{9}$.

12 24 $\frac{2}{315}$ $\frac{1}{315}$

12

LCM of fraction = \(\frac{LCM\;of\;numerator}{HCF\; of\;denominator}\) The given fractions are :  $\frac{2}{5}, \frac{3}{7}$, and $\frac{4}{9}$ LCM of 2, 3, 4 = 12 HCF of 5, 7, 9 = 1 The LCM of $\frac{2}{5}, \frac{3}{7}$, and $\frac{4}{9}$ is = \(\frac{12}{1}\) = 12