The capacitance of two condensers in parallel is four times their capacitance when they are connected in series. The ratio of the individual capacitances will be |
1 : 2 1 : 1 2 : 1 4 : 1 |
1 : 1 |
$C_1+C_2=4 \frac{C_1 C_2}{C_1+C_2}$ $\Rightarrow\left(C_1+C_2\right)^2=4 C_1 C_2$ $\Rightarrow\left(C_1-C_2\right)^2=0$ $\Rightarrow C_1=C_2$ |