The sum of the numbers between 100 and 1000 which are divisible by 14 is :

35392

numbers between 100 and 1000 which are divisible by 14 :-

112 , 126 , ......... , 994

Last term = a + ( n - 1 ) d

994 = 112 + ( n - 1 )14

882 = ( n - 1 )14

n = 64

Sum of all numbers = \(\frac{n}{2}\)(2a + ( n - 1 )d)

= \(\frac{64}{2}\)(2 × 112  + ( 63 ) 14 )

= 35392

The correct answer is option (2) : 35392