If sin(2x - 45°)= cos x and angle x and (2x - 45°) in degrees) are acute angles, then the value of cot x is:
Answer & explanation
Correct answer: option 3
sin(2x - 45°)= cos x
We know ,
sin A = cos B
So , A + B = 90º
⇒ sin(2x - 45°)= cos x
2x - 45° + x = 90°
3x = 135°
x = \(\frac{135° }{3}\) = 45°
Now , cotx = cot 45° = 1