In Young's double slit experiment, the 7th maximum with wavelength $λ_1$ is at a distance $d_1$ and that with wavelength $λ_2$ is at a distance $d_2$. Then $d_1/d_2$ is
Answer & explanation
Correct answer: option 1
$7β_1=d_1=7\frac{λ_1D}{2d}$ and $7β_2=d_2=7\frac{λ_2D}{2d}$
$∴\frac{d_1}{d_2}=\frac{λ_1}{λ_2}$