Suppose that the electric field amplitude of an electromagnetic wave is E0 = 120 N/c and its frequency is v = 50 MHZ. The expression for $\vec{E}$ is:
Answer & explanation
Correct answer: option 1
$B_0=\frac{E_0}{c}= \frac{120}{3 \times 10^8}=4 \times 10^{-7} \mathrm{~T}$
$\omega=2 \pi v=3.14 \times 10^8$ rad/s
$\lambda =\frac{c}{v}=\frac{3 \times 10^8}{5 \times 10^7}$ = 6 m
$k =\frac{2 \pi}{\lambda}$ = 1.05 rad/m
E = $E_0 \sin (kx-\omega t) $
$=120 \sin \left(1.05 x-3.14 \times 10^8 t\right)$