Two skaters have weight in the ratio 4 : 5 and are 9 m apart, on a smooth frictionless surface. They pull on a rope stretched between them. The ratio of the distance covered by them when they meet each other will be :
Answer & explanation
Correct answer: option 1
Acceleration of the skaters will be in the ratio - a1 : a2 = \(\frac{F}{4} : \frac{F}{5}\)
a1 : a2 = 5 : 4
According to question : S = 0 + \(\frac{1}{2}at^2\), we get :
\(\frac{S_1}{S_2} = \frac{a_1}{a_2}\)
S1 : S2 = 5 : 4