Two skaters have weight in the ratio 4 : 5 and are 9 m apart, on a smooth frictionless surface. They pull on a rope stretched between them. The ratio of the distance covered by them when they meet each other will be : 

5 : 4

Acceleration of the skaters will be in the ratio - a₁ : a₂ = \(\frac{F}{4} : \frac{F}{5}\)

a₁ : a₂ = 5 : 4

According to question : S = 0 + \(\frac{1}{2}at^2\), we get : 

\(\frac{S_1}{S_2} = \frac{a_1}{a_2}\)

S₁ : S₂ = 5 : 4