Three persons divided Rs.1720 in such a way that the ratio of first to the other two is 27:16. Find the\(\frac{1}{5}\)th part of the difference between the share of first and other two. |
80 440 88 90 |
88 |
Total amount = Rs.1720 A : B+C 27 : 16 Now → 27\(x\) + 16\(x\) = 1720 \(x\) = \(\frac{1720}{43}\) Difference = (27\(x\) - 16\(x\)) = \(\frac{1720}{43}\) × 11 = 440 \(\frac{1}{5}\)th of 440 = \(\frac{1}{5}\) × 440 = 88
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