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CUET
-- Mathematics - Section B1
Continuity and Differentiability
Find the value of k making the following function continuous at x = 5
$f(x)= \begin{cases}2 k x-1, & x ≥ 5 \\ 2 x+3, & x<5\end{cases}$
$\frac{5}{7}$
0
$\frac{5}{6}$
$\frac{7}{5}$
The correct answer is Option (4) → $\frac{7}{5}$