Find the value of k making the following function continuous at x = 5 $f(x)= \begin{cases}2 k x-1, & x ≥ 5 \\ 2 x+3, & x<5\end{cases}$

$\frac{5}{7}$ 0 $\frac{5}{6}$ $\frac{7}{5}$

$\frac{7}{5}$

The correct answer is Option (4) → $\frac{7}{5}$