Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Electrostatic Potential and Capacitance

Question:

The maximum electric field intensity on the axis of a uniformly charged ring of charge q and radius R will be

Options:

$\frac{1}{4 \pi \varepsilon_0} \frac{q}{3 \sqrt{3} R^2}$

$\frac{1}{4 \pi \varepsilon_0} \frac{2 q}{3 R^2}$

$\frac{1}{4 \pi \varepsilon_0} \frac{2 q}{3 \sqrt{3} R^2}$

$\frac{1}{4 \pi \varepsilon_0} \frac{3 q}{2 \sqrt{2} R^2}$

Correct Answer:

$\frac{1}{4 \pi \varepsilon_0} \frac{2 q}{3 \sqrt{3} R^2}$

Explanation:

Maximize the expression of electric field on the axis of ring.