If S is a point on side QR ofa triangle PQR such that QS = 10 cm. QR = 18 cm and ∠PSR = ∠QPR , then the length of PR will be:

16 cm 12 cm 15 cm 14 cm

12 cm

We have, QS = 10 cm QR = 18 cm ∠PSR = ∠QPR According to the question, In ΔPQR and ΔSPR ∠PSR = ∠QPR ∠R = ∠R [common] So, ΔPQR ~ ΔSPR = \(\frac{ QR}{ PR }\) = \(\frac{ PR}{ SR }\) = \(\frac{ 18}{ PR }\) = \(\frac{ PR}{8 }\) = PR2 = 144 = PR = 12 cm