If m and n are order and degree of the equation $(\frac{d^2y}{dx^2})^3+4.\frac{(\frac{d^2y}{dx^2})^3}{\frac{d^3y}{dx^3}}+\frac{d^3y}{dx^3}=x^2-1$ then:
Answer & explanation
Correct answer: option 2
All power of derivative term are rational.
So, $(\frac{d^3y}{dx^3})(\frac{d^2y}{dx^2})^3+4(\frac{d^2y}{dx^2})^3+(\frac{d^3y}{dx^3})^2=(x^2-1)\frac{d^3y}{dx^3}⇒m = 3,n=2$