A screw gauge has least count of 0.01 mm and there are 50 divisions in its circular scale. The pitch of the screw gauge is :
Answer & explanation
Correct answer: option 2
Least count of screw gauge = $\frac{Pitch}{(Number of division on circular scale)}$
⇒ 0.01 mm = $\frac{Pitch}{50}$
⇒ Pitch = 0.5 mm